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Saturday, September 02, 2006


PowerShell : Can you do that less cryptic ?

Ok,Oh, all right

the onliner from last post (" PowerShell : How can I tell witch numbers are missing from a sequence of numbers found in a text file ?  ,

gc test.txt | sort {[int]$_} |% {$i = 1}{while ($i -lt $_){$i;$i++};$i++}

was maybe a bit to tiny to post without any explanation.

you can do very powerfull things on the commandline like this, but for in a script or example this might not very handy.

 I still not going to explain it,

but I will make it a lot more Clear what Happens, by showing that you do not have too be so tiny in PowerShell , you can write this in a more verbose and readable way , as the former one-liner Can also be written as Follows :


# Read numbers from file 

$numbers = get-content test.txt

# Sort the Numbers

$Sortednumbers = $Numbers | Sort {[int]$_}

# start comparing numbers in file to counter

$counter = 1

foreach ($number in $Sortednumbers ) {

  # as long as Number in file is higher than counter, output as missing and raise counter  

  while ($counter -lt $Number){
    "$Counter is missing"

  # counter is the same as Number, hence is in file output and raise counter

  "$Counter is In file"


 This code does exactly the same as the on-liner, is a bit more work, but much more clear for code you or somebody else might have to read or change.

*Edit* some other suggestions given on IRC for handling this question are :


# Other suggestions on IRC
# <dreeschkind> 

$n = gc test.txt
$n|%{[int]$max = 1}{if ($max -lt $_){$max=$_}}
diff -r $(1..$max) $n

# <mow001> slower

$n = gc test.txt
$max = ($n | Measure-Object -max).maximum
diff -r $(1..$max) $n

# <d2d> faster ?
$result = @(); $arr = Get-Content test.txt; for ($i = 1; $i -lt $arr[-1]; $i++) { if ($arr -notcontains $i) { $result += $i } }; $result

*Edit 2*  Another tip : Need for speed, use another cool feature from Powershell go .NET directly : 



Greetings, /\/\o\/\/
Tags : Monad msh PowerShell

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